Support #1709
log file of ctlike
| Status: | Closed | Start date: | 02/24/2016 | |
|---|---|---|---|---|
| Priority: | Normal | Due date: | ||
| Assigned To: |  Knödlseder Jürgen | % Done: | 100% | |
| Category: | - | |||
| Target version: | - | |||
| Duration: |
Description
Dear the system admin
Hi, my name is Tan.
I found that the log file cannot be opened by the following python code.
...
logfile=“ctlike_"+str(ibin)+".log”
ctl = ctlike()
ctl.logFileOpen(logfile)
...
This code worked with the old ctools version. Maybe this is a bug (or an intentional change?). Can you change it work
Thank you for reading me.
Tan
Recurrence
No recurrence.
History
#1
Updated by Knödlseder Jürgen almost 9 years ago
- Tracker changed from Bug to Support
- Status changed from New to Feedback
- Assigned To set to Knödlseder Jürgen
- % Done changed from 0 to 100
I inspected the change log and could not find any moment where the logFileOpen() method accepted a filename (you can pass a Boolean parameter to specify whether a new log file should be written, logFileOpen(True), or whether the the logger should append to an existing log file, logFileOpen(False); maybe you passed the logfile as Boolean parameter).
The correct way to do what you want is setting the logfile parameter before opening the log file, i.e.
logfile = "ctlike_"+str(ibin)+".log" ctl = ctlike() ctl["logfile"] = logfile ctl.logFileOpen()Note that
logFileOpen() has to be called after ctl["logfile"] since logFileOpen() will open the file and use the value of the logfile parameter that exists at that time.#2
Updated by Dang Viet Tan almost 9 years ago
Thank you. I’ve already checked it.
#3
Updated by Knödlseder Jürgen almost 9 years ago
- Status changed from Feedback to Closed